Calculated Footing Width for Residential and Light Commercial Structures
Introduction
For residential structures that fall outside the limitations of the prescriptive code, and for most of all other structures, our foundation element features will need to be calculated. In this particular lesson we will limit our scope to structures with relatively low loads on soils – or we could say – relatively low-rise structures. This particular focus is convenient, and also appropriate, as you, the Architect, may well want to tackle such designs yourself. Larger structures, on the other hand, will be `over your head’ and for which you will likely contract with a Structural Engineer. Footings for larger structures will be covered later. Many of the same design principles apply. And, whether you have your Structural Engineer do all, or just some, of your foundation designs – in any case you still want to be able to `speak the language’.
Note: this article formerly contained introductory material on loads and forces. That material has been moved (here).
Calculated Footing Width Example
Consider the following conditions:
Building: 40 ft wide
Roof: 2 x 12 rafter construction similar to example above with ridge beam down middle
Eaves: 18 in.
2 stories with both floors bearing on ext. foundation and int. slab footing via int. bearing wall down middle.
Frost depth 30 in.
Allowable soil bearing pressure 1500 psf
Roof, walls, and floors: light frame wood construction
Wall heights (floor to ceiling) 9 ft
Loads:
40 psf SL
40 psf LL
Assumed dead loads …
12 psf for roofs (on plan area)
10 psf for floors
10 psf for ext walls
Let’s calculate the load on the exterior foundation wall bearing soil, and determine a minimum footing width.
First, the total load via the exterior wall on the bearing soil …
RSL … Ã?½ of 20 ft x 40 psf = 400 plf …
RDL … Ã?½ of 20 ft x 12 psf = 120 plf
Eave SL … 2* x 40 psf x 18/12 ft = 120 plf SL …
Eave DL … 12 x 18/12 = 18 plf DL
Upper Wall DL … 9 ft x 10 psf = 90 plf
Upper FLL … Ã?½ of 20 ft x 40 psf = 400 plf
Upper FDL … Ã?½ of 20 x 10 = 100 plf
Main Wall DL … 90 plf
Main FLL … 400 plf
Main FDL … 100 plf
Total Superstructure Load on Foundation …
DL … 120 + 18 + 90 + 100 + 90 + 100 = 518 plf
SL … 400 + 120 = 520 plf SL
LL … 400 + 400 = 800 plf LL
TOTAL LOAD = TL … 518 + 520 + 800 = 1838 plf
*Note: SL is generally double over eave for ice damming.
Let’s use 8 in. foundation wall thickness …
Min. foundation wall height (assuming footing thickness of 8 in.) is …
frost depth + 8 in. clear to top of foundation = wall height + footing depth
gives … wall height of 30 + 8 – 8 = 30 in.
Now we will calculate the weight of the foundation … (or estimate it) …
Stem wall weight …
ÃÂ? DL, sw = Ã?³ x A = 150 lb/ft3 (8/12 ft)(30/12 ft) = 250 plf
NOTE: we will use �³ = 150 pcf for reinforced concrete.
Let’s try a footing width of 16 in., and thickness of 8 in.
ÃÂ? DL, sw = Ã?³ x A = 150 lb/ft3 (8/12 ft)(16/12 ft) = 133 plf
So, our line load on the soil is … 1838 + 250 + 133 = 2221 plf
Now we will use the following equation …
fp = ÃÂ? / width
where fp = bearing pressure on soil
So,
fp = 2221 plf / (16/12 ft) = 1666 psf
The design check is …
IS fp = applied bearing pressure on soil âÂ?¤ the allowable soil bearing pressure? …
Or, is 1666 psf âÂ?¤ 1500 psf? … No, not quite …
Let’s try 18 in. footing …
Revising the footing weight …
ÃÂ? DL, sw = Ã?³ x A = 150 lb/ft3 (8/12 ft)(18/12 ft) = 150 plf
Total line load becomes …
1838 + 250 + 150 = 2238 plf
fp = 2238 plf / (18/12 ft) = 1492 psf
Or, is 1492 psf âÂ?¤ 1500 psf? … YES, GOOD!
So, …
… 8 x 30 in. foundation wall on 8 x 18 footing … GOOD !!!
Concluding Remarks
We will determine reinforcement and other requirements in the next lesson (here).
NOTE: we have used the FULL Snow load simultaneous with the FULL Live load. The building codes recognize that the full Snow load is not likely to occur simultaneously with the full Live load, and vice versa, and may allow a reduced total when these two loads are taken simultaneously. We could use this provision to design a slightly smaller footing. An example where the reduced combination is used is … here. This (the linked) example also illustrates use of a truss roof system spanning from ext wall to ext wall and a slab on grade for the main floor.
References
Example Footing Width Calculation, Jeff Filler, Associated Content.